(X^2+6x+5)/(3x-2)=4

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Solution for (X^2+6x+5)/(3x-2)=4 equation: 



(X^2+6X+5)/(3X-2)=4

We move all terms to the left:

(X^2+6X+5)/(3X-2)-(4)=0



Domain of the equation: (3X-2)!=0

We move all terms containing X to the left, all other terms to the right

3X!=2

X!=2/3

X!=2/3

X∈R



We multiply all the terms by the denominator


(X^2+6X+5)-4*(3X-2)=0

We multiply parentheses

(X^2+6X+5)-12X+8=0

We get rid of parentheses

X^2+6X-12X+5+8=0

We add all the numbers together, and all the variables

X^2-6X+13=0

a = 1; b = -6; c = +13;
Δ = b2-4ac
Δ = -62-4·1·13
Δ = -16
Delta is less than zero, so there is no solution for the equation

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